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mysql - 根据sql中的另一个表显示所有日期的计数?

In lại Tác giả: Walker 123 更新时间:2023-11-29 02:10:27 27 4
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我有两个表,一个是日历,第二个是 final_registration,如下所示:

我的日历表:

*--------------------*
| S.No. | datefield |
*--------------------*
| 1 | 2019-01-01 |
| 2 | 2019-01-02 |
| 3 | 2019-01-03 |
| 4 | 2019-01-04 |
| 5 | 2019-01-05 |
| 6 | 2019-01-06 |
| 7 | 2019-01-07 |
| 8 | 2019-01-08 |
| 9 | 2019-01-09 |
| 10 | 2019-01-10 |
| 11 | 2019-01-11 |
| 12 | 2019-01-12 |
| 13 | 2019-01-13 |
| 14 | 2019-01-14 |
| 15 | 2019-01-15 |
| 16 | 2019-01-16 |
| 17 | 2019-01-17 |
| 18 | 2019-01-18 |
| 19 | 2019-01-19 |
| 20 | 2019-01-20 |
| 21 | 2019-01-21 |
| 22 | 2019-01-22 |
| 23 | 2019-01-23 |
| 24 | 2019-01-24 |
| 25 | 2019-01-25 |
| 26 | 2019-01-26 |
| 27 | 2019-01-27 |
| 28 | 2019-01-28 |
| 29 | 2019-01-29 |
| 30 | 2019-01-30 |
| 31 | 2019-01-31 |
---------------------

我的第二张 table :

*-----------------------------------------*
| id | event_id | name | booking_date |
*-----------------------------------------*
| 1 | 101 | Ritu | 2019-01-15 13:21 |
| 2 | 101 | Seeta | 2019-01-15 18:21 |
| 3 | 101 | Geeta | 2019-01-16 13:21 |
| 4 | 102 | Wasim | 2019-01-16 14:21 |
| 5 | 102 | Rahul | 2019-01-17 13:21 |
| 6 | 101 | Gagan | 2019-01-17 14:21 |
| 7 | 101 | Sunny | 2019-01-17 15:21 |
| 8 | 101 | Aman | 2019-01-17 16:21 |
-------------------------------------------

我正在尝试以下输出:

*--------------------*
| datefield | count |
*--------------------*
| 2019-01-01 | 0 |
| 2019-01-02 | 0 |
| 2019-01-03 | 0 |
| 2019-01-04 | 0 |
| 2019-01-05 | 0 |
| 2019-01-06 | 0 |
| 2019-01-07 | 0 |
| 2019-01-08 | 0 |
| 2019-01-09 | 0 |
| 2019-01-10 | 0 |
| 2019-01-11 | 0 |
| 2019-01-12 | 0 |
| 2019-01-13 | 0 |
| 2019-01-14 | 0 |
| 2019-01-15 | 2 |
| 2019-01-16 | 1 |
| 2019-01-17 | 3 |
---------------------

今天是 1 月 17 日,所以我需要输出到当前日期。我试过查询,但没有给我 1 月 1 日至 1 月 14 日的查询

SELECT calendar.datefield, COUNT(calendar.datefield)
FROM calendar
LEFT JOIN final_registration
ON DATE_FORMAT(calendar.datefield, '%Y-%m-%d') = DATE_FORMAT(final_registration.booking_date, '%Y-%m-%d')
WHERE DATE_FORMAT(calendar.datefield, '%Y-%m-%d') <= DATE_FORMAT( CURDATE(), '%Y-%m-%d' )
AND DATE_FORMAT(calendar.datefield, '%Y-%m') = DATE_FORMAT( CURDATE(), '%Y-%m' )
AND final_registration.event_id = '101'
GROUP BY DATE_FORMAT(calendar.datefield, '%Y-%m-%d')

我的查询给了我以下结果:

*--------------------*
| datefield | count |
*--------------------*
| 2019-01-15 | 2 |
| 2019-01-16 | 1 |
| 2019-01-17 | 3 |
*--------------------*

我已经尝试了很多但无法得到我的结果。

câu trả lời hay nhất

您通过在 WHERE 子句中包含条件,使您的 LEFT 连接成为 INNER 连接。试试这个:

SELECT calendar.datefield, COUNT(calendar.datefield)
FROM calendar
LEFT JOIN final_registration
ON DATE_FORMAT(calendar.datefield, '%Y-%m-%d') = DATE_FORMAT
(final_registration.booking_date, '%Y-%m-%d')
AND final_registration.event_id = '101'
WHERE DATE_FORMAT(calendar.datefield, '%Y-%m-%d') <= DATE_FORMAT( CURDATE(), '%Y-%m-%d' )
AND DATE_FORMAT(calendar.datefield, '%Y-%m') = DATE_FORMAT( CURDATE(), '%Y-%m' )
GROUP BY DATE_FORMAT(calendar.datefield, '%Y-%m-%d')

关于mysql - 根据sql中的另一个表显示所有日期的计数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54236785/

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Walker 123
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