我正在做一个学校项目。
这里是项目的链接 http://www.dsu-class.com/zito82/lab10/
我需要使用 MVC 模型来编写 PHP 应用程序。除了一个步骤,我已经完成了所有步骤。我需要在客户列表中添加一个更新输入按钮。我从这个输入按钮启动到更新表单。当我提交此表单时,它应该会更新客户数据。
我有两个问题。我通过 foreach 循环创建了客户列表,并为每个更新按钮分配了一个 customerID,但是一旦我传递到表单,我就无法拉出 customerID 以通过该表单。
第二个问题是我的表单没有更新MYSQL数据库。
明确地说,我必须遵循这个 MVC 结构。构建 php 文件而不是函数对我来说会容易得多,但这就是我应该这样做的方式。
这是我的代码。我首先列出了 Controller ,其次是模型,最后是 View 。
require('../model/database.php');
require('../model/customer-db.php');
if (isset($_POST['action'])) {
$action = $_POST['action'];
} else if (isset($_GET['action'])) {
$action = $_GET['action'];
} khác {
$action = 'display_customers';
}
if ($action == 'display_customers') {
$customers = get_customers();
include '../view/customer-list.php';
}
else if ($action == 'view_customerData') {
$customerID = $_GET['customerID'];
view_customerData($customerID);
include '../view/customer-information.php';
}
else if ($action == 'update_customer') {
$customerID = $_POST['customerID']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName'];
$address = $_POST['address']; $city = $_POST['city']; $state = $_POST['state']; $postalCode = $_POST['postalCode'];
$countryCode = $_POST['countryCode']; $phone = $_POST['phone']; $email = $_POST['email'];
update_customer($customerID, $firstName, $lastName, $address, $city, $state, $postalCode, $countryCode, $phone, $email);
$customers = get_customers();
include '../view/customer-list.php';
}
else if ($action == 'delete_customer') {
$customerID = $_POST['customerID'];
delete_customer($customerID);
$customers = get_customers();
include '../view/customer-list.php';
}
else if ($action == 'under-construction') {
include('../under-construction.php');
} khác
?>
包含我对 Controller 的函数调用的模型
require_once('database.php');
function get_customers() {
global $db;
$query = "SELECT * FROM customers
ORDER BY lastName";
$customers = $db->query($query);
return $customers;
}
function delete_customer($customerID) {
global $db;
$query = "DELETE FROM customers
WHERE customerID = '$customerID'";
$db->exec($query);
}
function view_customerData ($customerID) {
global $db;
$query = "SELECT * FROM customers
WHERE customerID = '$customerID'";
$customerData = $db->query($query);
$customerData = $customerData->fetch();
return $customerData;
}
function update_customer($customerID, $firstName, $lastName, $address, $city, $state, $postalCode, $countryCode, $phone, $email) {
global $db;
$query = "UPDATE customers
SET
firstName = '$firstName', lastName = '$lastName', address = '$address', city = '$city', state = '$state',
postalCode = '$postalCode', countryCode = '$countryCode', phone = '$phone', email = '$email'
WHERE customerID = '$customerID' ";
$db->exec($query);
}
?>
我的看法
客户 ListView
Customer List
Tên |
Email Address |
Country Code |
|
|
---|
|
|
|
|
|
客户更新表单 View
我相信这会解决您的问题,但我假设您标记为 “Customer Update Form View” 的表单位于 customer-information.php
.
在问题顶部的任何文件中,对于 view_customerData
操作...
else if ($action == 'view_customerData') {
$customerID = $_GET['customerID'];
$customer = view_customerData($customerID); // note the return value is now assigned
include '../view/customer-information.php';
}
然后,在 customer-information.php
中,用数据预填表格。主要缺少的是客户 ID...
现在,我强烈建议您开始使用带有参数绑定(bind)的准备好的语句,而不是将值直接连接/插入到您的 SQL 查询中。
Tôi là một lập trình viên xuất sắc, rất giỏi!