假设我有 2 个或更多表,这些表由不同的列组成,其中不一定存在共享 key (id):
Alpha:
+----+-------+-------+-------+
| id | paula | randy | simon |
+----+-------+-------+-------+
| 1 | 8 | 7 | 2 |
| 2 | 9 | 6 | 2 |
| 3 | 10 | 5 | 2 |
+----+-------+-------+-------+
Beta:
+----+---------+-----+------------+------+
| id | is_nice | sex | dob | gift |
+----+---------+-----+------------+------+
| 2 | 1 | F | 1990-05-25 | iPod |
| 3 | 0 | M | 1990-05-25 | coal |
+----+---------+-----+------------+------+
Gamma:
+----+---------+--------+
| id | is_tall | is_fat |
+----+---------+--------+
| 1 | 1 | 1 |
| 99 | 0 | 1 |
+----+---------+--------+
期望的效果是在数据不可用的地方插入 NULL 时将表混合在一起:
+----+-------+-------+-------+---------+-----+------------+------+---------+--------+
| id | paula | randy | simon | is_nice | sex | dob | gift | is_tall | is_fat |
+----+-------+-------+-------+---------+-----+------------+------+---------+--------+
| 1 | 8 | 7 | 2 | | | | | 1 | 1 |
| 2 | 9 | 6 | 2 | 1 | F | 1990-05-25 | iPod | | |
| 3 | 10 | 5 | 2 | 0 | M | 1990-05-25 | coal | 1 | 1 |
| 99 | | | | | | | | 0 | 0 |
+----+-------+-------+-------+---------+-----+------------+------+---------+--------+
我可以使用 NULL 'dummy' 列和 UNION ( MySql SELECT union for different columns? ),但如果表的数量很大,这似乎是一种痛苦。我想我可以使用 JOIN 方法来完成此操作,但我需要一些帮助来解决这个问题。
Điều này hoạt động:
SELECT `id`, `paula`, `randy`, ..., NULL AS `is_nice`, ... FROM `Alpha`
UNION SELECT `id`, NULL AS `paula`, ..., FROM `Beta`
UNION SELECT `id`, NULL AS `paula`, ..., `is_fat` FROM `Gamma` ;
但这确实感觉像是错误的做法。每当我想添加其他表时,我如何才能获得相同的结果,而不必编辑一行又一行的 SQL 插入 NULL AS whatever
?
Cảm ơn trước!
SELECT
allid.id
, a.paula, a.randy a.simon
, b. ...
, c. ...
FROM
( SELECT id
FROM Alpha
UNION
SELECT id
FROM Beta
UNION
SELECT id
FROM Gamma
) AS allid
LEFT JOIN
Alpha AS a
ON a.id = allid.id
LEFT JOIN
Beta AS b
ON b.id = allid.id
LEFT JOIN
Gamma AS g
ON g.id = allid.id
如果表除了 NHẬN DẠNG
没有共享其他列,您可以使用简单的编写方式(但更容易破解):
SELECT
*
FROM
( SELECT id
FROM Alpha
UNION
SELECT id
FROM Beta
UNION
SELECT id
FROM Gamma
) AS allid
NATURAL LEFT JOIN
Alpha
NATURAL LEFT JOIN
Beta
NATURAL LEFT JOIN
Gamma
Tôi là một lập trình viên xuất sắc, rất giỏi!