我找不到 contentsOfURL
的任何替代方法来解决此问题。
这是我的 Swift 代码:
import Foundation
import MapKit
class MapHelper{
func geoCodeUsingAddress(address:String) ->CLLocationCoordinate2D{
var latitude = 0.0
var longitude = 0.0
let esc_addr = address.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)
let req = "http://maps.google.com/maps/api/geocode/json?sensor=false&address=\(esc_addr)"
let result:NSString? = NSString(contentsOfURL: NSURL(string: req)); // here is error //msg comes
if let value=result{
let scanner:NSScanner = NSScanner(string: value)
if(scanner.scanUpToString("\"lat\" :", intoString: nil) && scanner.scanString("\"lat\" :", intoString: nil)){
scanner.scanDouble(&latitude)
}
if(scanner.scanUpToString("\"lng\" :", intoString: nil) && scanner.scanString("\"lng\" :", intoString: nil)){
scanner.scanDouble(&longitude);
}
}
khác{
}
var center:CLLocationCoordinate2D = CLLocationCoordinate2D(latitude: 0, longitude: 0);
center.latitude = latitude;
center.longitude = longitude;
return center;
}
}
thử cái này
let urlPath: String = "YOUR URL HERE"
let data = NSString(contentsOfURL: urlPath, encoding: NSASCIIStringEncoding, error: nil)
Tôi là một lập trình viên xuất sắc, rất giỏi!