想在消息中显示每个字符的十六进制(如果可能的话,简单的方法,我知道我可以遍历字符并执行此操作):
typedef struct{
double dTime;
char cMessage[11];
} typeCanMessage;
typeCanMessage cmMessage1 = {4.5, {0xd2, 0xf1, 0xe0, 0xf1, 0xf1, 0xf1, 0xf1, 0x23, 0x23, 0x23, 0x23}};
QMessageBox *msgBox = new QMessageBox(0);
msgBox->setGeometry(QRect(QPoint(200,200),QSize(400,400)));
msgBox->setInformativeText(QString::number(cmMessage1.dTime, 'f', 8) + " "
+ QString::number(cmMessage1.cMessage, 'x')); // <-- something like this perhaps
msgBox->exec();
错误:“调用重载的‘number(char[11], char)’不明确”
修改:
sprintf(cM, "%x", &cmMessage1.cMessage);
QMessageBox *msgBox = new QMessageBox(0);
msgBox->setGeometry(QRect(QPoint(200,200),QSize(400,400)));
msgBox->setInformativeText(QString::number(cmMessage1.dTime, 'f', 8) + " "
+ (QString)cM); // <-- something like this perhaps
msgBox->exec();
结果:bfb123d8//错误
我想避免执行以下操作(循环或不循环):
sprintf(cM, "%X%X%X%X%X%X%X%X%X%X%X", cmMessage1.cMessage[0],
cmMessage1.cMessage[1],
cmMessage1.cMessage[2],
cmMessage1.cMessage[3],
cmMessage1.cMessage[4],
cmMessage1.cMessage[5],
cmMessage1.cMessage[6],
cmMessage1.cMessage[7],
cmMessage1.cMessage[8],
cmMessage1.cMessage[9],
cmMessage1.cMessage[10]);
循环:
for(int i = 0; i < 11; i++){
sprintf(cM + 2 * i, "%X", cmMessage1.cMessage[i]);
}
number
函数只是格式化一个数字。如果你想格式化数组中的每个数字,你需要一个循环,按照
auto text = QString::number(cmMessage1.dTime, 'f', 8) + " ";
for (unsigned c : cmMessage1.cMessage) {
text += QString::number(c,16);
}
msgBox->setInformativeText(text);
(您还应该使用 ký tự không dấu
, thay vì ký tự
,来存储 8 位无符号值)。
Tôi là một lập trình viên xuất sắc, rất giỏi!